Lake Homes Realty
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600 e sanford street

LAKE ALFRED, FL 33850

$320,000

3 BEDS 2-Full BATHS
0.31 AC LOT
Residential - Single Family
Image 1
Bedrooms 3
Total Baths 2
Full Baths 2
Acreage 0.32
Status Off Market
MLS # P4931274
County Polk
More Info
Category Residential - Single Family
Status Off Market
Acreage 0.32
MLS # P4931274
County Polk
The property you are inquiring about is located in Lake Alfred, FL in the East area of Polk County. This is just a gem in the easy-access area of Lake Alfred. Located on a corner lot of 100x141 with privacy fence, screened patio for entertaining around the pool. This beautiful 3 bedroom, 2 bathroom home, with open floorplan and durable tile throughout, nice fireplace in the gathering area, with new kitchen granite-topping, plus an additional flex room for lifestyle convenience, two-car garage, and a full-service house generator. Fabulous value in NO HOA! **Agents, please see MLS remarks.**
Location not available

Exterior Features

  • Construction Single Family Residence
  • Siding Block, Brick
  • Roof Metal
  • Garage No
  • Water Public
  • Sewer Public Sewer
  • Lot Dimensions 100x141

Interior Features

  • Appliances Dishwasher, Disposal, Range, Range Hood, Refrigerator
  • Heating Central
  • Cooling Central Air
  • Basement Slab
  • Fireplaces 1
  • Fireplaces Description Wood Burning
  • Year Built 1975

Neighborhood & Schools

  • Subdivision LAKE VIEW SUB UNIT NO 2 PB 13 PG 5

Financial Information

  • Parcel ID 26-27-33-515500-000820
  • Zoning R-1A

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